The sum of the measures of two complementary angles exceeds the difference of their measures by 72°. Find the measure of the smaller angle

Complementary angles are pair of two non-right angles whose sum is equal to 90°Let the two complementary angles be : Δ and ФGiven : Sum of the measures of two complementary angles exceed the difference of their measures by 72°[tex]:\implies[/tex]  Δ + Ф - 72° = Δ - Ф[tex]:\implies[/tex]  2Ф = 72°[tex]:\implies[/tex]  Ф = 36°As Δ and Ф are complementary, their sum should be equal to 90°[tex]:\implies[/tex]  Δ + 36° = 90°[tex]:\implies[/tex]  Δ = 90° - 36°[tex]:\implies[/tex]  Δ = 54°So, Complementary angles are 54° and 36°Answer : The Measure of the Smaller Angle is 36°