A baseball team played 32 games and lost 8. Katy was the catcher in 5/8 of the winning games and 1/4 of nthe losing games.a. What fraction of the games did the team win?b. In how many games did Katy play catcher?

Answer: fraction of the games did the team win is = [tex]\frac{3}{4}[/tex]Katy play game  = 17 Step-by-step explanation:given data baseball team played = 32 gameslost = 8 Katy catcher = 5/8 of winningKaty catcher =  1/4  of losingto find outWhat fraction of the games did the team win and  how many games did Katy playsolutionwe know total game = 32 and lost 8 so win is total - lost = 32 - 8 = 24 so fraction of the games did the team win is = [tex]\frac{\frac{24}{8} }{\frac{32}{8} }[/tex]   fraction of the games did the team win is = [tex]\frac{3}{4}[/tex]andso total game 24 winning is  [tex]\frac{5}{8}[/tex]so katy winning is  [tex]24*\frac{5}{8}[/tex]katy winning = 3 × 5 = 15 and losing  [tex]\frac{1}{4}[/tex]total lose game 8 so Katy  lose = 8 ×  [tex]\frac{1}{4}[/tex] = 2 so Katy play game = 15 + 2 = 17