Solve using cross multiplication method, ax + by = a^2 ; bx + ay = b^2

Answer: x=a²+ab+b²/a+b , y=-ab/a+bStep-by-step explanation:The system of the given equation may b written as:ax+by-a²=0bx+ay-b²=0Here,a1=a,b1=b,c1= -a²a2=b,b2=a and c2= -b²By cross multiplication we getx/b*(-b²)-(-a²)*a = -y/a*(-b²)-(-a²)*b = 1/a*a-b*bx/-b³+a³ = -y/-ab²+a²b  = 1/a²-b²Nowx/-b³+a³ = 1/a²-b²x=a³-b³/a²-b²x=(a-b)(a²+ab+b²)/(a-b)(a+b)x=a²+ab+b²/a+bAnd,-y/-ab²+a²b = 1/a²-b²-y=a²b -ab²/a²-b²y=ab²-a²b/a²-b²y=ab(b-a)/(a-b)(a+b)y= -ab(a-b)/(a-b)(a+b)y= -ab/a+bHence x=a²+ab+b²/a+b , y=-ab/a+b....